Answer to Question #192643 in Chemistry for itrhd

Question #192643

A chemist needs to neutralize 25.5 L of 3.86 M chloric acid (HClO3) What mass of sodium hydroxide is needed to accomplish this


1
Expert's answer
2021-05-13T02:09:06-0400

HClO3 + NaOH = NaClO3 + H2O

According to the equation, n (HClO3) = n (NaOH).

CM = n / V

n = CM x V

n (HClO3) = 3.86 x 25.5 = 98.43 mol

n (HClO3) = n (NaOH) = 98.43 mol

n = m /M

M (NaOH) = 40 g/mol

m (NaOH) = n x M = 98.43 x 40 = 3937.2 g


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