Answer to Question #192643 in Chemistry for itrhd

Question

A chemist needs to neutralize 25.5 L of 3.86 M chloric acid (HClO3) What mass of sodium hydroxide is needed to accomplish this

Answer 1

HClO₃ + NaOH = NaClO₃ + H₂O

According to the equation, n (HClO₃) = n (NaOH).

C_M = n / V

n = C_M x V

n (HClO₃) = 3.86 x 25.5 = 98.43 mol

n (HClO₃) = n (NaOH) = 98.43 mol

n = m /M

M (NaOH) = 40 g/mol

m (NaOH) = n x M = 98.43 x 40 = 3937.2 g