Question #192124

What is the pressure (in atm) exerted by 5.00 moles of nitrogen gas contained in a 82.1 Liter container at 400 K? Only type in the number for your answer.

Expert's answer

P = unknown

V = 82.1 L

n = 5.00 mol

R = 0.0821 atm L mol^{-1} K^{-1}

T = 400 K

**Solution:**

The Ideal Gas equation can be used.

The Ideal Gas equation can be expressed as: PV = nRT

Divide to isolate P:

P = nRT / V

Plug in the numbers and solve for P:

P = (5.00 mol × 0.0821 atm L mol^{-1} K^{-1} × 400 K) / (82.1 L) = 2 atm

**P = 2 atm**

**Answer: 2**

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