Answer to Question #192124 in Chemistry for heather

Question

What is the pressure (in atm) exerted by 5.00 moles of nitrogen gas contained in a 82.1 Liter container at 400 K? Only type in the number for your answer. 

Answer 1

P = unknown

V = 82.1 L

n = 5.00 mol

R = 0.0821 atm L mol^-1 K^-1

T = 400 K

Solution:

The Ideal Gas equation can be used.

The Ideal Gas equation can be expressed as: PV = nRT

Divide to isolate P:

P = nRT / V

Plug in the numbers and solve for P:

P = (5.00 mol × 0.0821 atm L mol^-1 K^-1 × 400 K) / (82.1 L) = 2 atm

P = 2 atm

Answer: 2