What is the pressure (in atm) exerted by 5.00 moles of nitrogen gas contained in a 82.1 Liter container at 400 K? Only type in the number for your answer.
P = unknown
V = 82.1 L
n = 5.00 mol
R = 0.0821 atm L mol-1 K-1
T = 400 K
The Ideal Gas equation can be used.
The Ideal Gas equation can be expressed as: PV = nRT
Divide to isolate P:
P = nRT / V
Plug in the numbers and solve for P:
P = (5.00 mol × 0.0821 atm L mol-1 K-1 × 400 K) / (82.1 L) = 2 atm
P = 2 atm