Answer to Question #191310 in Chemistry for Elessia

Question

How many liters of nitric acid solution, with a concentration of 0.05 mol / dm3, can be made if we have 150 cm3 of 60% nitric acid, whose density is 1.37 g / cm3?

Answer 1

Solution:

Calculate the mass of nitric acid solution:

Mass of HNO₃ solution = Solution volume × Density of solution

Mass of HNO₃ solution = 150 cm³ × 1.37 g/cm³ = 205.5 g

Calculate the mass of nitric acid (HNO₃) in the solution:

Mass of HNO₃ = Mass of HNO₃ solution × w(HNO₃)

Mass of HNO₃ = 205.5 g × 0.6 = 123.3 g

Calculate the moles of nitric acid (HNO₃) in the solution:

Moles of HNO₃ = Mass of HNO₃ / Molar mass of HNO₃

The molar mass of HNO₃ is 63.01 g mol^-1.

Moles of HNO₃ = (123.3 g) / (63.01 g mol^-1) = 1.9568 mol

Calculate liters of nitric acid solution:

Liters of HNO₃ solution = Moles of HNO₃ / Molarity of HNO₃

Liters of HNO₃ solution = (1.9568 mol) / (0.05 mol dm^-3) = 39.137 dm³ = 39.14 L

Answer: 39.14 L of nitric acid solution.