56.9 liters of Carbon dioxide would contain how many moles at STP?
Carbon dioxide - CO2
At Standard Temperature and Pressure (STP), one mole of any gas occupies a volume of 22.4 L.
Thus 56.9 L of CO2 is:
(56.9 L) × (1 mol / 22.4 L) = 2.54 mol CO2
2.54 mol of CO2 occupies a volume equal to 56.9 L.
Answer: 2.54 mol CO2