Answer to Question #190031 in Chemistry for Caylin Adams

Question

Good day

My question is:

What mass of KIO₃ is needed to convert the copper in 0.3500g of CuSO₄.5H₂O to Cu(IO₃)₂

Please assist

Answer 1

CuSO₄.5H₂O + 2KIO₃ = Cu(IO₃)₂ + K₂SO₄ + 5H₂O

n (KIO₃) = 2 x n (CuSO₄.5H₂O)

n = m / M

M (CuSO₄.5H₂O) = 250 g/mol

n (CuSO₄.5H₂O) = 0.3500 / 250 = 0.0014 mol

n (KIO₃) = 2 x 0.0014 = 0.0028 mol

M (KIO₃) = 214 g/mol

m (KIO₃) = n x M = 0.0028 x 214 = 0.6 g