Answer to Question #173755 in Chemistry for adel perez

Question

Determine the molarity of a NaOH solution when each of the following amounts of acid neutralizes 25.0 mL of the NaOH solution.

5.00 mL of 0.250 M HNO3

Answer 1

Solution:

The balanced chemical equation:

NaOH + HNO₃ → NaNO₃ + H₂O

According to the equation above: n(NaOH) = n(HNO₃)

n = MV

Dilution equation can be used.

Dilution equation is expressed as:

M₁V₁ = M₂V₂

where

M = molarity of solution

V = volume of solution

Thus:

M(NaOH) × V(NaOH) = M(HNO₃) × V(HNO₃)

M(NaOH) × (25.0 mL) = (0.250 M) × (5.00 mL)

M(NaOH) = (0.250 M × 5.00 mL) / (25.0 mL) = 0.05 M

M(NaOH) = 0.05 M

Answer: The molarity of a NaOH solution is 0.05 M.