Answer to Question #16610 in Chemistry for jq

Question

Potassium hydrogen phthalate (KHC8H4O4, molar mass 204.2 g/mol) is frequently used to standardize solutions of NaOH. The reaction is:
NaOH(aq) + KHC8H4O4(aq) --> H2O(l) + NaKC8H4O4(aq)

Calculate the mass of potassium hydrogen phthalate needed to react with 30 mL of 0.10 M NaOH.

Answer 1

n of NaOH -------- 30 ml
0.1 mol in 1000 ml

n=0.003 mol


0.003 m
NaOH(aq) + KHC8H4O4(aq) ---> H2O(l) + NaKC8H4O4(aq)
204.2

m=0.003*204.2=0.6126 g