Question #16242

Find mass of sodium chloride (in Ib) required to prepare 100 gallons of 2.0 M solution of sodium chloride

Expert's answer

2.0 M means 2 mol per liter

3.785 liters in 1 gallons

378.5 liters

in 100 gallons

2 mol -------------- 1 L

x

-----------------378.5 L

x=757 mol

n =m/Mm

m= n * Mm= 757 *

58.5 = 44284.5 g =44.2845 kg

3.785 liters in 1 gallons

378.5 liters

in 100 gallons

2 mol -------------- 1 L

x

-----------------378.5 L

x=757 mol

n =m/Mm

m= n * Mm= 757 *

58.5 = 44284.5 g =44.2845 kg

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