Answer to Question #15642 in Other Chemistry for Abdullah

Question #15642
a gaseous organic compound X was burnt in the excess of oxygen.A 0.112 dm3 sample of X measured at s.t.p produced 0.88 grams of CO2 how many carbon atoms are present in one molecule of x ?
1
Expert's answer
2012-10-03T09:00:00-0400
If organic compound X has formula C(x)H(y)O(z), the reaction is
C(x)H(y)O(z)
+ k O2 = x CO2 + (y/2) H2O

IUPAC has defined standard reference
conditions as being 0 °C and 100 kPa (1 bar)
R = 8.314×10−2
L*bar*K(-1)*mol(-1)
pV = nRT
n = pV/(RT)
n(X) = 1 bar * 0.112 L /
(8.314×10−2 L*bar*K(-1)*mol(-1) * 273 K) = 0.005 mol
n(CO2) = 0.88 g / 44
g/mol = 0.02 mol

x = n(CO2)/n(X) = 0.02 / 0.005 = 4
Four carbon atoms
are present in one molecule of X.

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Comments

Assignment Expert
21.10.20, 21:41

Dear Faiza,
Questions in this section are answered for free. We can't fulfill them all and there
is no guarantee of answering certain question but we are doing our best. And if answer
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Faiza
15.10.20, 22:26

I didn't get why we have to calculate the no of moles from general gas equation and how did we know that they are for CO2?

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