CaCO3+2HCl=CaCl2+H2CO3
n (CaCO3) = n (CaCl2)
m (CaCO3)=25 g
M (CaCO3)=100.1 g/mol
n (CaCO3)=m/M = 25/100.1 = 0.25 mol
n (CaCl2)=n (CaCO3) = 0.25 mol
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