Answer to Question #13041 in Chemistry for Suresh kumar

Question

100g nitrogen mixed with 92g hydrogen
a) identity the limiting reagent
b) calculate the weight of amonia form
c) which reactent remains and how much

Answer 1

n of N2 = 100/14=3.57 moles
n of H2= 92/2 =46 H2 is in access ,so N2 is
limiting reagent,and H2 remains (46-3*3.57=35.29)


3.57
2*3.57
N2 + 3H2 = 2NH3

m of NH3 is 2*3.57*17=121.38 g