Answer to Question #12741 in Other Chemistry for Molly
__CO2(g) + __H2O(l) __C6H12O6(s) + __O2(g)
What is the mass of glucose (180.18 g/mol) produced from 2.20 g of CO2?
6CO2(g) + 6H2O(l) ---> C6H12O6(s) + 6O2
m = 2.20*180.18/(6*44) = 1.5015 g
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