Answer to Question #12739 in Other Chemistry for Molly
__FeBr3(s) + __AgNO3(aq) → __AgBr(s) + __Fe(NO3)3(aq)
FeBr3(s) + 3AgNO3(aq) = 3AgBr(s) + Fe(NO3)3(aq)
m = 295.55*0.188/(3*187.77) = 0.986 g
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