Answer to Question #97262 in Organic Chemistry for Anthony

Question

A 0.3259g of (KPH) required 20.15ml of NaOH for neutralization. Calculate the molarity of NaOH

Answer 1

Answer on Question #97262 – Chemistry – Organic Chemistry

Task:

A 0.3259g of (KPH) required 20.15ml of NaOH for neutralization. Calculate the molarity of NaOH.

Solution:

"KHP" - potassium hydrogen phthalate (KHC₈H₄O₄, Molar mass = 204.2 g/mol).

KHP has one acidic hydrogen atom, and reacts with NaOH on a 1:1 stoichiometric basis:

KHC₈H₄O₄ + NaOH = NaKC₈H₄O₄ + H₂O.

Then,

n(KHP) = n(NaOH);

m(KHP) / M(KHP) = C_m(NaOH)*V(NaOH);

C_m(NaOH) = m(KHP) / (M(KHP*V(NaOH);

C_m(NaOH) = 0.3259 / (204.2 * 0.02015) = 0.0792 (mol/L).

Answer: C_m(NaOH) = 0.0792 mol/L.