Answer to Question #9717 in Organic Chemistry for sam
2H2O = 4NaOH + O2
3.2 g of O2 corresponds to 0.1 mol of O2
quantity of NaOH is 4*0.1=0.4 mol
The mass of NaOH is m(NaOH) =
M(NaOH)*n(NaOH) = 40g/mol * 0.4 mol = 16 g
Answer: 16 grams of NaOH are
produced when 3.20 grams of O2 is formed.
Need a fast expert's response?Submit order
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!