Answer to Question #968 in Organic Chemistry for bami
2 C4H6 (g) ----> C8H12 (l)
The reaction is second order in C4H6.
(a) What is the rate law for the reaction, and;
(b) if the rate constant is 4.0 x 10-2 M-1& s-1, and the initial concentration of C4H6 is 0.200 M, how long will it take for the concentration of C4H6 to reach 0.04 M?
1/[C4H6] - 1/[C4H6]0 = kt
b. The intial concentration is 0.200 M, and the final concentration is 0.200 M. K is 0.84 L/mol min, so
1/0.040 M - 1/0.200 M = 4.0 x 10-2 M-1 s-1 * t
t = 500 s = 8.33 min.
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