Answer on Question #83431, Chemistry/ Organic Chemistry
A sample solution containing sulfate ions (SO42−) was analyzed and was found to contain 5 mol of sulfate ions (SO42−).
Calculate the equivalent of sulfate ions (SO42−) present in the solution.
Equivalent weight of sulphate = 96.07/2= 48.04 g/equivalent
5 mol will have a weight of = 5*96.07 = 480.35 g
The equivalent of sulfate ions = 480.35/48.04 = 10.00 eq
Answer: 10.00 eq