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Answer to Question #59497 in Organic Chemistry for Emaley Weatherly
Question #59497
how many grams of lead 2 sulfate would be produced from the complete reaction of 23.6 grams of lead 2 oxide
Expert's answer
Lead (II) sulphate can be prepared by lead(II) oxide by warm sulphuric acid according to the following reaction:
23.6g xg
PbO+H2SO4=PbSO4+H2O
1m 1m
According to the stechiometric equation 1 mole of PbSO4 is produced from 1 mole of the PbO, so the amount of the PbSO4 will be calculated from the proportion x=(23,6×1)÷1=23.6g
x=23.6g
23.6g xg
PbO+H2SO4=PbSO4+H2O
1m 1m
According to the stechiometric equation 1 mole of PbSO4 is produced from 1 mole of the PbO, so the amount of the PbSO4 will be calculated from the proportion x=(23,6×1)÷1=23.6g
x=23.6g
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