Answer to Question #54166 in Organic Chemistry for Laiba bhat
Rate law for the rxn of OH negative with tertiary Butyl bromide to form an elimination product in 75 % ethanol and 25 % water at 30°C is :- r = 7.1 × 10^-5 ( tertiary butyl bromide ) (OH^-) + 1.5 ×10^-5 ( tertiary Butyl bromide ). What %age of the rxn takes place by E2 pathway when :- a) (OH^-)= 5M , b) = 0.0025 M ?
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