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Answer to Question #51532 in Organic Chemistry for olgamykytsey

Question #51532
Ethanoic acid (HC[sub]2[/sub]H3O[sub]2[/sub]) may be produced from ethyne (C[sub]2[/sub]H[sub]2[/sub]) by the following overall
reaction:
2 C[sub]2[/sub]H[sub]2[/sub](g) + 2 H[sub]2[/sub]O(l) + O[sub]2[/sub](g) ---&gt; 2HC[sub]2[/sub]H[sub]3[/sub]O[sub]2[/sub] (l)

Calculate Ho for the production of ethanoic acid using the following thermochemical
equations:
C[sub]2[/sub]H[sub]4[/sub](g) ---&gt; H[sub]2[/sub](g) + C[sub]2[/sub]H[sub]2[/sub](g) Î”Ho = 174.5 kJ
C[sub]2[/sub]H[sub]5[/sub]OH(l) ---&gt; C[sub]2[/sub]H[sub]4[/sub](g) + H[sub]2[/sub]O(l) Î”Ho = 44.07 kJ
C[sub]2[/sub]H[sub]5[/sub]OH(l) + O[sub]2[/sub](g) ---&gt; HC[sub]2[/sub]H[sub]3[/sub]O[sub]2[/sub](l) + H[sub]2[/sub]O(l) Î”Ho = - 495.2 kJ
2 H[sub]2[/sub](g) + O[sub]2[/sub](g) ---&gt; 2 H[sub]2[/sub]O(l) Î”Ho = - 571.7 kJ
1
2015-06-08T07:01:39-0400
Hess's law problem. By adding theequations (or the equation for the reverse reaction) you can arrive at theÂ equation for the target reaction. Then add the enthalpy changes for eachÂ reaction to find the enthalpy change for the target reaction. If you reverse aÂ reaction, then reverse the sign on Î”H. If you change the coefficients by someÂ factor, use the same factor for Î”H.Â

Target reactionÂ
2C2H2(g) + 2H2O(l) + O2(g) --> 2HC2H3O2(l).......... Î”H

2H2(g) + 2C2H2(g) --> 2C2H4(g).................................Î”H = 2(-174.5 kJ)Â
2C2H4(g) + 2H2O(l) --> 2C2H5OH(l)...........................Î”H = 2(-44.07 kJ)Â
2C2H5OH(l) + 2O2(g) ---> 2HC2H3O2(l) +2H2O(l) ....Î”H = 2(-495.2 kJ)Â
2H2O(l) --> 2H2(g) + O2(g).................... ......................Î”H = +571.1 kJÂ
----------------------- ------------------------------------------- ----------------------------Â
2C2H2(g) + 2H2O(l) + O2(g) --> 2HC2H3O2(l).......... Î”H = -856.44 kJ

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