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Answer to Question #41716 in Organic Chemistry for Sumit

Question #41716
CH3-C(=O)-CH=CH2 gives two different products when treated with NaCN,HCN;
1)product -> H3C-C(OH)(CN)-CH=CH2 at temperature 5-10 degree C
2)product -> H3C-C(=O)-CH2-CH2-CN at temperature 80 degree C.
-Explain.
Expert's answer
The first reaction product occurs under kinetically controlled conditions. Its formation is reversible, so this product can be isolated only at low temperatures. The rate of the second product formation is lower, yet it is more thermodynamically stable. Therefore, under the thermodynamically controlled conditions this product will be accumulated in the reaction mixture.

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