Question #33015

acetylene burn in air forming carbon di-oxide and water vapour calculate the volume of air required to completely burn 50 cm cube

Expert's answer

C_{2}H_{2} + 5/2O_{2} ----------------> 2CO_{2} + H_{2}O

Burning of 1 mole of C_{2}H_{2} requires 2.5 mole O_{2}

That means 2.5 x 50 cm^{3} = 125 cm^{3} O_{2}

Let total air required is = M

20% of air = 125 cm^{3} O_{2}

20 M/100 = 125 cm^{3} O_{2}

M = 125 cm^{3} x 100/20 = 625 cm^{3}

Answer: 625 cm^{3}

Burning of 1 mole of C

That means 2.5 x 50 cm

Let total air required is = M

20% of air = 125 cm

20 M/100 = 125 cm

M = 125 cm

Answer: 625 cm

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