Answer to Question #3142 in Organic Chemistry for mellisa
For the reaction
?CH[sub]3[/sub]OH + ?O[sub]2[/sub] => ?HCO[sub]2[/sub]H + ?H[sub]2[/sub]O,& & what is the maximum amount of HCO[sub]2[/sub]H(46.0254 g/mol) which could be formed from
10.61 mol of CH[sub]3[/sub]OH (32.0419 g/mol) and13.09 mol of O[sub]2[/sub] (31.9988 g/mol)?Answer in units of g.
The balanced equation is CH3OH + O2 --> HCO2H + H2O so, only 10.61 mol of CH3OH could react with 10.61 mol of O2. ν(HCO2H) = ν(O2) = 10.61 mol. m(HCO2H) = 46.0254 [g/mol] * 10.61 mol = 488.3250 g.