Answer to Question #288038 in Organic Chemistry for pihu

Question

a patient with Weight 76kg must be injected the solution of NaHCO³ in the concentration of 0.66mol/kg .howany millilitres of this solution with the weight fraction of 4.2ust be taken?

Answer 1

if 1kg= 0.66mol

76kg= ?

= (76×0.66)/1= 50.16moles

if 76kg= 50.16moles

4.2 kg = ?

(4.2×50.16)/76

=2.772millilitres