Answer to Question #28553 in Organic Chemistry for Mubashir
n(Fe) = m / Ar
n(Fe) = 76.2 gm/56 a.m.u. = 1.36 mol
n(S) = m / Ar
n(S) = 86.7gm/32 a.m.u. = 2.7 mol
Starting from the equation:
Fe(x) + S (p) ==> FeS (p)
Starting from the equation, it is seen that the sulfur in excess, thuslimiting reagent is iron.
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