# Answer to Question #27964 in Organic Chemistry for Morgan

Question #27964

what mass of FeCl3 is required to prepare 100mL of 0.250 M FeCl3 solution?

Expert's answer

To calculate the amount of FeCl

C

Where

C

n - amount in moles

V - volume of solution

n(FeCl

n(FeCl

To calculate the mass of FeCl

m(FeCl

Where

M - molar mass

n - amount in moles

M(FeCl

M(FeCl

m(FeCl

_{3}, we can use the formula:C

_{m}= n(FeCl_{3})/V_{solution}Where

C

_{m}- molar concentrationn - amount in moles

V - volume of solution

n(FeCl

_{3}) = C_{m}* V_{solution}n(FeCl

_{3}) = 0.250 M * 0.1L = 0.025 molesTo calculate the mass of FeCl

_{3}, we can use the formula:m(FeCl

_{3}) = n(FeCl_{3}) * M(FeCl_{3})Where

M - molar mass

n - amount in moles

M(FeCl

_{3}) = Ar(Fe) +3*Ar(Cl)M(FeCl

_{3}) = 56 + 3 * 35.5 = 162.5 g/molesm(FeCl

_{3}) = 0.025 moles * 162.5 g/moles = 4.0625 g**So, the final answer is 4.0625 g of FeCl**_{3}Need a fast expert's response?

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