Answer to Question #23850 in Organic Chemistry for emily
i = 1 so m = 0.49 / 5.02 = 0.09760 moles of adrenalin / kg of CCl4
also we have 0.64 g in 36.0 g of solvent or 0.64 x 1000 / 36 g of adrenalin /kg of solvent = 17.778 g
so in 1 liter of the solution we have 17.778 g = 0.09760 moles
1 mole of adrenalin has mass of 17.778 / 0.09760 = 182 g
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