With reasons, arrange the following: ( 4mks)
(i) In increasing order of basic strength: C6H5NH2, C6H5N(CH3)2, (C2H5)2 NH and CH3NH2.
(ii) In increasing order of boiling point: C2H5OH, (CH3)2NH, C2H5NH2
Due to the −I effect of C6
H5 group, the electron density on N-atom C6
H5−NH2 is lower than that on the N-atom (C6
H5)2NH . But in case of C6H5N(CH3)2, two CH3
group attached with N atom which increases the electron density on N-atom and in CH3−NH3
only +I effect of methyl group increases the basicity of the compound
(CH3)2 NH < C2H5NH2 < C2H5OH
Note: Stronger H-bonding, more b.p more solubility Alcohol > Amine In amines on H attached to N takes part in H-bond.