How many grams of oxygen (O₂) react with 4.2 mol of iron (Fe) in the rusting reaction? 4Fe + 3O₂ ⟶ 2Fe₂O₃
Moles of "O_2=\\frac{3\u00d74.2}{4}=" 3.15
Mass of "O_2=32\u00d73.15= 100.8grams"
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