64 723
Assignments Done
99,4%
Successfully Done
In September 2018

Answer to Question #16693 in Organic Chemistry for Mitch

Question #16693
What volume of .06892 M NaOH is required to react completely with 41.25-mLof .06053 M H2SO4?
Expert's answer
n of H2SO4 in 41.25 ml is equal to
0.06053 mol in 1000 ml

n of acid
=0.002497 mol

H2SO4 + 2NaOH=Na2SO4 + H2O

n of NaOH =2*n of H2SO4 =
0.004994 mol

0.004994 mol in x ml
0.06892 mol in 1000
ml

x=72.46 ml

Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be first!

Leave a comment

Ask Your question

Submit
Privacy policy Terms and Conditions