Question #12932

C3H8+5O2->3CO2+4H2O
Caculate the amount in cubic meters of air ( 21% oxygen) required when 10 cubic feet of it is burned?

Expert's answer

10 cubic feet = 283.168466 L

volume is proportional to equivalents in

equation

C3H8 : O2 like 1:5

so, for burning we

need 283.168466*5=1415.842 L

1415.842 L is

21%

x-------------100%

x=6742.106 L of air or 6.742 m3 of air

volume is proportional to equivalents in

equation

C3H8 : O2 like 1:5

so, for burning we

need 283.168466*5=1415.842 L

1415.842 L is

21%

x-------------100%

x=6742.106 L of air or 6.742 m3 of air

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