Answer to Question #125635 in Organic Chemistry for Gift

Question

2.65g of anhydrous sodium trioxocarbonate (IV) were dissolved in water and made up to 250cm^3. 25cm^3 of this solution required 20cm^3 of hydrochloric acid of complete neutralization.

(a) The concentration of sodium trioxocarbonate (vii) in g/dm^3
(b) the concentration in mole per dm^3
(c) Write the equation for the reaction.

Answer 1

a)

1 dm³ = 1000 cm³

2.65g x 1000cm3 / 250cm3 = 10.6 g/dm³;

b)

M (Na₂CO₃) = 106 g/mol

n (Na₂CO₃) = 10.6g / 106g/mol = 0.1 mol

[Na₂CO₃] = 0.1 mol/dm³;

c)

Na₂CO₃(aq) + 2HCl(aq) --> 2NaCl(aq) + CO₂(g) + H₂O(l).