Question #12028

A balloon containing 0.81 mol of helium gas has a volume of 8.8 L. What will the volume, in liters, of the balloon be if some of the helium is lost and only 0.41 mol remain? The pressure and temperature remain constant.

Expert's answer

The volume will be

(8.8 L) x (0.41 / 0.81) = 4.5 L.

(8.8 L) x (0.41 / 0.81) = 4.5 L.

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