Answer to Question #9823 in Inorganic Chemistry for Sharmin Hoque
The solubility of AlCl(3) is 46.6 grams in 100 mL in water. How many grams of AlCl(3) will dissolve in 1.68 L?
1.68 L of water dissolves 46.6*1.68/0.1=782.88 grams of AlCL3.
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