Answer to Question #98200 in Inorganic Chemistry for Shane Jessica Ballera

Question

1. Octane, C8H18, is a substance in premium gasoline. How many moles are in 95.0 grams of octane?

2. What is the mass of 1.2 X 10^24 molecules of O2

3. How many moles are in 9.52g of MgCl2

4. How many moles are present in 180 grams of NaOH?

5. What is the mass in grams of 10.0 X 10^6 SO2 molecules?

Answer 1

(1) 114.23 g of Octane = 1 mole

95 g. of Octane = (1/114.23) * 95 = 0.83 moles

(2) 6.023 * 10²³ molecules = 32 g of O₂

1.12 * 10²⁴ molecules = (32/6.023*10²³) * 1.12 * 10²⁴ = 59.5 g.

(3) 95.2 g. of MgCl₂ = 1 mole

9.52 g of MgCl2 = 0.1 mole

(4) 40 g of NaOH = 1 mole

180 g of NaOH = 180/40 = 4.5 moles

(5) 6.023 * 10²³ molecules = 64 g

10⁷ molecules = (64/6.022*10²³ )* 10⁷

= 10.62 * 10^-16 g.