Answer to Question #98200 in Inorganic Chemistry for Shane Jessica Ballera

Question #98200
1. Octane, C8H18, is a substance in premium gasoline. How many moles are in 95.0 grams of octane?

2. What is the mass of 1.2 X 10^24 molecules of O2

3. How many moles are in 9.52g of MgCl2

4. How many moles are present in 180 grams of NaOH?

5. What is the mass in grams of 10.0 X 10^6 SO2 molecules?
1
Expert's answer
2019-11-11T07:48:07-0500

(1) 114.23 g of Octane = 1 mole

95 g. of Octane = (1/114.23) * 95 = 0.83 moles


(2) 6.023 * 1023 molecules = 32 g of O2

1.12 * 1024 molecules = (32/6.023*1023) * 1.12 * 1024 = 59.5 g.


(3) 95.2 g. of MgCl2 = 1 mole

9.52 g of MgCl2 = 0.1 mole


(4) 40 g of NaOH = 1 mole

180 g of NaOH = 180/40 = 4.5 moles


(5) 6.023 * 1023 molecules = 64 g

107 molecules = (64/6.022*1023 )* 107

= 10.62 * 10-16 g.


Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

Assignment Expert
02.03.21, 13:01

Dear Ythan, You're welcome. We are glad to be helpful. If you liked our service please press like-button beside answer field. Thank you!

Ythan
02.03.21, 08:34

THANKS

Leave a comment

Ask Your question

LATEST TUTORIALS
New on Blog
APPROVED BY CLIENTS