First, we should calculate the mass of each element in this amount of the fuel:
Three elements will be oxidized through the combustion process (carbon, hydrogen and sulfur):
Nitrogen will be oxidized only under conditions close to those in the internal combustion engine.
Now, we must calculate the amount in moles of carbon, hydrogen, sulfur and oxygen in the fuel:
Lets calculate the total amount in moles of the oxygen required for the oxidation of the fuel. We also should not forget about oxygen in the fuel, which is also involved into the oxidation process ():
Now, we have to found the equivalent volume of pure oxygen measured under normal conditions:
Finally, we all know - the air contains approximately 1/5 volume part of pure oxygen:
Thus, 400 kg of this fuel requires approx. 3775 m3 of air and this is the theoretical minimum, which does not involve oxidation of nitrogen etc.