Answer to Question #90716 in Inorganic Chemistry for Aziz

Question

Given the following reaction:
Cu+2AgNO3=2Ag+Cu(NO3)2
How many moles of zag will be produced from 46.0 g of Cu, assuming AgNO3 is available in excess?

Answer 1

First, the amount of Cu should be calculated:

n = m / Mr,

where m - mass, Mr - molecular weight, n - number of moles.

n (Cu) = 46 g / 64 g/mol = 0.72 mol.

As AgNO₃ is available in excess, the amoumt of produced Ag equals the amount of reacting Cu.

As a result, 0.72 mol of 2Ag or 1.44 mol of Ag will be produced in the given reaction.

Answer: 1.44 mol of Ag or 0.72 mol of 2Ag.