First, the amount of Cu should be calculated:
n = m / Mr,
where m - mass, Mr - molecular weight, n - number of moles.
n (Cu) = 46 g / 64 g/mol = 0.72 mol.
As AgNO3 is available in excess, the amoumt of produced Ag equals the amount of reacting Cu.
As a result, 0.72 mol of 2Ag or 1.44 mol of Ag will be produced in the given reaction.
Answer: 1.44 mol of Ag or 0.72 mol of 2Ag.