n(Na2CO3) = C(Na2CO3) × V(Na2CO3) = 0.035 mol L-1 × 0.25 L = 0.00875 mol.
m(Na2CO3) = n(Na2CO3) × M(Na2CO3) = 0.00875 mol × (2×23 + 12 + 3×16) = 0.9275 g = 927.5 mg.
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