Answer to Question #75314 in Inorganic Chemistry for Meg

Question #75314
Describe how you would prepare a 2.00 L of 0.100 M KrCrO4 from 1.75 M K2CrO4 stock solution
1
Expert's answer
2018-03-31T08:48:08-0400
n (KrCrO4) = 2 * 0.1 = 0.2M
V(1.75 M KrCrO4) = 0.2 /1.75 = 0.114 L

Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be the first!

Leave a comment

Ask Your question

LATEST TUTORIALS
New on Blog
APPROVED BY CLIENTS