Answer to Question #69001 in Inorganic Chemistry for Jenna

Question

If 35.00g of carbon dioxide (CO2) gas is mixed with 15.00g of calcium oxide (CaO) to produce calcium carbonate (CaCO3), what is the limiting reactant and how much (in g) calcium carbonate is expected?

Answer 1

CO2 + CaO → CaCO3
35.00g CO2 x (1 mol CO2/ 44 g CO2) x (1 mol CaCO3 /1 mol CO2) x (100.09g CaCO3 /1 mol CaCO3) = 79.6 g CaCO3
15.00g CaO x (1 mol CaO/ 56.07 CaO) x (1 mol CaCO3 /1 mol CaO) x (100.09g CaCO3 /1 mol CaCO3) = 22.8 g CaCO3
The reactant that produces a smaller amount of product is the limiting reagent
Therefore CaO is the limiting reagent in this reaction.
Answer: CaO is the limiting reagent; calcium carbonate is expected 22.8 g