Answer to Question #65270 in Inorganic Chemistry for Hisham

Question

Electrolysis of Dilute sodium nitrate.
Q:Write the half-equation for anode and cathode reactions.

Answer 1

Solution:
When diluted sodium nitrate will be electrolysis of water:
Then half-reaction at the cathode and anode will look like this:
At the cathode:
C (-): 2H20 + 2e = H2 + 2OH-
At the anode:
A (+): 2H2O - 4e = O2 + 4H+
Answer: C (-): 2H20 + 2e = H2 + 2OH- ; A (+): 2H2O - 4e = O2 + 4H+.