Answer to Question #63701 in Inorganic Chemistry for ravi

Question

Q 1. The equilibrium constant for the reaction H2(g) +I2(s) <~> 2HI(g), is .35 at 298 K .In the following mixture at 298 K , has equilibrium been reached? If not, state on which side of the equilibrium the system is :
(1) PH2 =0.1atm PHI =0.8 ATM and I2 is solid in the containercontainer.

Answer 1

The equilibrium constant is K = [HI]^2/[H2] or 0.8^2/0.1 = 6.4. It is higher than 0.35 and the equilibrium is on the side of HI.