# Answer to Question #56540 in Inorganic Chemistry for jasmine

Question #56540

On heating to dryness, 3.10g of a hydrated salt produced 2.02g of anhydrous salt.The formula of the hydrated salt is represented as M.xH2O. If the molecular mass of salt M is 202g/mol , what is the value of x ?

ans: A. 4

B. 5

C. 6 ( )

D. 7

ans: A. 4

B. 5

C. 6 ( )

D. 7

Expert's answer

Solution

M*xH2O = M + xH2O

n(H2O) = (3.10-2.02)/18 = 0.06

n(M*xH2O) = 3.10/(202 + 18x)

n(M*xH2O) = x*n(H2O)

3.10/(202+18x) = x*0.06

0.015 + 0.17x = 0.06x

X = 7

Answer

D. 7

M*xH2O = M + xH2O

n(H2O) = (3.10-2.02)/18 = 0.06

n(M*xH2O) = 3.10/(202 + 18x)

n(M*xH2O) = x*n(H2O)

3.10/(202+18x) = x*0.06

0.015 + 0.17x = 0.06x

X = 7

Answer

D. 7

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