Answer to Question #56431 in Inorganic Chemistry for silvia

Question

Calculate the equilibrium concentration of NH3,Cu^2+,[ Cu(NH3)]^2+ ,[Cu(NH3)2]^2+,[Cu(NH3)3]^2+,and[Cu(NH3)4]^2+ in a solution made by mixing 500.0 ml of 3.00 M NH3 with 500.0 ml of 2.00*10^-3 M Cu(NO3)2. The sequential equilibria are

Cu^2+ +NH3---->[Cu(NH3)]^2+ ka1=1.86x10^4
[Cu(NH3)]^2++NH3----->[Cu(NH3)2]^2+ k2= 3.88x10^3
[Cu(NH3)2]^2+ +NH3----->[Cu(NH3)3]^2+ k3=1.00x10^3
[Cu(NH3)3]^2+ +NH3----->[Cu(NH3)4]^2+ k4=1.55x10^2