A procedure similar to that described in this experiment can be used to precipitate Cl- as AgCl. A sample containing chloride weighing 0.207 g was precipitated with Ag+, and the AgCl produced weighed 0.472 g. Calculate the mass % of Cl- in the original sample.
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Expert's answer
2015-11-04T09:29:10-0500
Ag+ + Cl- = AgCl n(Cl) = n(AgCl) = m(AgCl)/MW(AgCl); m(Cl) = nCl AW(Cl); w(Cl) = m(Cl/msample) = (m(AgCl) AW(Cl))/(msample MW(AgCl)) w(Cl) = (0.472 g 35.45 g mol-1)/(0.207 g 143.3182 g mol-1) = 56.4 %
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