Answer to Question #53514 in Inorganic Chemistry for Najirul haq
iodine is more soluble in H2O in presene of I-
As iodine is non-polar molecule it has lower solubility in polar solvent (water). However, upon addition of any iodide salt, its solubility considerably increases. It can be explained by the fact that iodine reacts with I- to form a complex salt (I-3) : I2 + KI → KI3 Since K+I-3 is a polar substance it is highly soluble in water. Therefore, KI provides higher solubility of iodine in water.