Answer to Question #52665 in Inorganic Chemistry for Tajnur

Question

Q- 3 g C^2H^4 gas requires oxygen gas ( O^2) for combustion which is obtained from pure Potassium Chlorate ( KClO^3). Mass of Potassium Chlorate is ____ ?

Answer 1

C₂H₄ + 3O₂ = 2CO₂+2H₂O
From the equation, 1 mole of C₂H₄ requires 3 moles of O₂ for combustion.
Consequently 3 g of C₂H₄requires X grams of O₂
X = 3·3/1 = 9 (grams of O₂)

2KClO₃ = 2KCl + 3O₂
From the equation, 3 moles of O₂ are produced from 2 moles of Potassium Chlorate,
So 9 grams of O₂ areproduced from Y grams of Potassium Chlorate
Y = 9·2/3 = 6 (grams of KClO₃)
Answer: 6 grams