Answer to Question #52337 in Inorganic Chemistry for Candidate

Question #52337
Question
Historically chlorine gaz, cl2 has been used do disinfect drinking and swimming pool waters. Knowing that chlorine gas reacts in water according to the following reaction:
CL2+H2O=HOCL+H+CL
and that the manufacturer of bleach water certifies that in 100 g of their product there are 10.8 g of NaCl (the other 89.2 g filling material with no relation at all with disinfection), that HOCl is a weak acid that dissociates as follows:
HOCl = H + OCl , pK= 7.54
Show that the 10.8 g of NaOCl is equivalent to 10.3 g of Cl2
1
Expert's answer
2015-06-23T07:41:44-0400
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