Answer to Question #52337 in Inorganic Chemistry for Candidate

Question

Question
Historically chlorine gaz, cl2 has been used do disinfect drinking and swimming pool waters. Knowing that chlorine gas reacts in water according to the following reaction:
CL2+H2O=HOCL+H+CL
and that the manufacturer of bleach water certifies that in 100 g of their product there are 10.8 g of NaCl (the other 89.2 g filling material with no relation at all with disinfection), that HOCl is a weak acid that dissociates as follows:
HOCl = H + OCl , pK= 7.54
Show that the 10.8 g of NaOCl is equivalent to 10.3 g of Cl2