# Answer to Question #47761 in Inorganic Chemistry for Shabreka Edwards

Question #47761

What mass of melamine, C3N3(NH2)3, will be obtained from 137.0kg of urea, CO(NH2)2, if the yield of the overall reaction is 77.0% ?

Express your answer to three significant figures and include the appropriate units.

Express your answer to three significant figures and include the appropriate units.

Expert's answer

6 (NH

M(urea) = 60 kmoles/kg

From 6 x 60 kg of urea it is produced 126 kg of melamine;

From 137.0 kg – X kg

X = 47.95 kg (of melamine)

If the yield is 77% so the mass of melamine will be 47.95 x 0.77 = 36.9215kg

Answer:

_{2})_{2}CO → C_{3}H_{6}N_{6}+ 6 NH_{3}+ 3 CO_{2}_{}M(urea) = 60 kmoles/kg

From 6 x 60 kg of urea it is produced 126 kg of melamine;

From 137.0 kg – X kg

X = 47.95 kg (of melamine)

If the yield is 77% so the mass of melamine will be 47.95 x 0.77 = 36.9215kg

Answer:

**~36.922 kg**Need a fast expert's response?

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