# Answer to Question #4671 in Inorganic Chemistry for Steven

Question #4671

Predict the spin-only magnetic moment of Ru3+(aq) if Δ0 = 24700 cm-1 and the electron

pairing energy is 280 kJ/mol.

pairing energy is 280 kJ/mol.

Expert's answer

The spin-onlymagnetic moment is determined by the formula:

μ = √(n(n+2), n is

Theelectron pairing energy is P = 280 kJ/mol = 23406 cm

Δ

μ = √(n(n+2) = √(1(1+2) = √3 = 1.73 mB

Thespin-only magnetic moment of Ru3+(aq) is 1.73 mB.

μ = √(n(n+2), n is

Theelectron pairing energy is P = 280 kJ/mol = 23406 cm

^{-1}Δ

_{0}> P, thus thecomplex is high-spin, the number of unpaired electrones is 1.μ = √(n(n+2) = √(1(1+2) = √3 = 1.73 mB

**Answer:**Thespin-only magnetic moment of Ru3+(aq) is 1.73 mB.

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