Answer on Inorganic Chemistry Question for Steven
pairing energy is 280 kJ/mol.
μ = √(n(n+2), n is
Theelectron pairing energy is P = 280 kJ/mol = 23406 cm-1
Δ0> P, thus thecomplex is high-spin, the number of unpaired electrones is 1.
μ = √(n(n+2) = √(1(1+2) = √3 = 1.73 mB
Thespin-only magnetic moment of Ru3+(aq) is 1.73 mB.
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