Answer to Question #4671 in Inorganic Chemistry for Steven

Question

Predict the spin-only magnetic moment of Ru3+(aq) if Δ0 = 24700 cm-1 and the electron
pairing energy is 280 kJ/mol.

Answer 1

The spin-onlymagnetic moment is determined by the formula:
μ = √(n(n+2), n is
Theelectron pairing energy is P = 280 kJ/mol = 23406 cm^-1
Δ₀> P, thus thecomplex is high-spin, the number of unpaired electrones is 1.
μ = √(n(n+2) = √(1(1+2) = √3 = 1.73 mB
Answer:
Thespin-only magnetic moment of Ru3+(aq) is 1.73 mB.